If the density of gasoline is 0.66 g/ml , how many kilocalories of energy are obtained from 2.7gal of gasoline?
note:When 1.0g of gasoline burns, 11,500 kcal of energy are given off.
energy=energy/gram*grams
= energy/gram*density*volume
so convert 2.7gal to ml, and do the math.
To determine the number of kilocalories of energy obtained from 2.7 gallons of gasoline, we need to follow these steps:
Step 1: Convert the volume of gasoline from gallons to milliliters.
Since we are given that the density of gasoline is 0.66 g/ml, we need to determine how many milliliters are in 2.7 gallons.
1 gallon is equal to 3,785.41 milliliters.
So, 2.7 gallons is equal to 2.7 x 3,785.41 = 10,239.327 milliliters.
Step 2: Calculate the mass of 2.7 gallons of gasoline.
Using the density of gasoline, we can calculate the mass.
Density = Mass / Volume
Rearranging the equation, Mass = Density x Volume
Mass = 0.66 g/ml x 10,239.327 ml = 6,755.116 g
Step 3: Calculate the energy obtained from the mass of gasoline burned.
We are given that when 1.0g of gasoline burns, 11,500 kcal of energy are released.
So, to calculate the energy obtained from burning 6,755.116 g of gasoline, we can use the following proportion:
1 g -> 11,500 kcal
6,755.116 g -> x kcal
Cross multiplying, we have:
x kcal = (6,755.116 g * 11,500 kcal) / 1 g
x kcal = 77,577,937.4 kcal
Therefore, approximately 77,577,937.4 kilocalories of energy are obtained from 2.7 gallons of gasoline.