Graham's Law predicts that the ratio of the rate of effusion of gas X to the rate of gas Y equals the square root of the INVERTED ratio of their molar masses:
Rate of X/Rate of Y = SQRT(My/Mx)
What is the ratio of rate of effusion of Helium to Nitrogen gas? Enter your answer to two decimal places.
I got 1.87 as my answer, but apparently that's not right.
Why didn't you show how you came up with that answer? I could have found the error.
To calculate the ratio of the rate of effusion of Helium (He) to Nitrogen (N2) gas, we need to use Graham's Law. Graham's Law states that the ratio of the rate of effusion of two gases is equal to the square root of the ratio of their molar masses.
The molar mass of Helium (He) is approximately 4 grams/mol, and the molar mass of Nitrogen (N2) is approximately 28 grams/mol.
Using Graham's Law equation:
Rate of He / Rate of N2 = square root (molar mass of N2 / molar mass of He)
Substituting the values:
Rate of He / Rate of N2 = square root (28 / 4)
Calculating the square root:
Rate of He / Rate of N2 = square root (7)
Taking the square root of 7, we get approximately 2.65.
Therefore, the ratio of the rate of effusion of Helium to Nitrogen gas is approximately 2.65, rounded to two decimal places.
Note: It's important to double-check the molar masses used in the calculation and ensure that the calculations are performed accurately.