find an equation of i line given the slope and one point on the line
m=2;(3,2)
use y = mx + b
since m=2 ,so far we would have
y = 2x + b, but (3,2) lies on this line, so
2 = 2(3) + b
b = -4
y = 2x - 4
To find the equation of a line given the slope (m) and one point (x1, y1) on the line, we can use the point-slope form of a linear equation:
y - y1 = m(x - x1)
Substituting the given values, m = 2 and the point (3, 2):
y - 2 = 2(x - 3)
Now, we can simplify this equation to get it in slope-intercept form (y = mx + b), where b is the y-intercept:
y - 2 = 2x - 6
y = 2x - 6 + 2
y = 2x - 4
Therefore, the equation of the line with the given slope of 2 and passing through the point (3, 2) is y = 2x - 4.
To find the equation of a line given the slope and one point on the line, you can use the point-slope formula. The point-slope formula is:
y - y₁ = m(x - x₁)
where (x₁, y₁) is the given point on the line, and m is the slope.
Let's apply this formula to your problem:
Given: m = 2 and (x₁, y₁) = (3, 2)
Substitute the values into the point-slope formula:
y - 2 = 2(x - 3)
Next, simplify the equation:
y - 2 = 2x - 6
Now, rearrange the equation to get it into slope-intercept form (y = mx + b):
y = 2x - 4
Therefore, the equation of the line with a slope of 2 passing through the point (3, 2) is y = 2x - 4.