Question

Calculate the magnitude of the electrostatic force the two down quarks inside a neutron exert on each other if they are separated by a distance of 0.71 fm.

Answer 1

Use coulombs law.

Answer 2

with which formula?

Answer 3

[AI-generated answer — Explain Bot]

To calculate the magnitude of the electrostatic force between two quarks, we can use Coulomb's law. Coulomb's law states that the magnitude of the electrostatic force between two charged particles is given by the equation:

F = (k * |q1 * q2|) / r^2

where F is the magnitude of the electrostatic force, k is the electrostatic constant (approximately equal to 8.99 × 10^9 N m^2/C^2), |q1| and |q2| are the magnitudes of the charges on the particles, and r is the distance separating them.

In the case of two down quarks inside a neutron, each down quark has a charge of -1/3e, where e is the elementary charge. The magnitude of the charge is therefore |q1| = |q2| = 1/3e.

Substituting the values into the equation, we get:

F = ((8.99 × 10^9 N m^2/C^2) * |(1/3e) * (1/3e)|) / (0.71 fm)^2

Before we proceed with the calculation, we need to convert the femtometer (fm) to meters. 1 femtometer is equal to 1 x 10^-15 meters. Therefore, 0.71 fm is equal to 0.71 x 10^-15 meters.

Now, substituting the values, we get:

F = ((8.99 × 10^9 N m^2/C^2) * |(1/3e) * (1/3e)|) / (0.71 x 10^-15 m)^2

Simplifying further,

F = ((8.99 × 10^9 N m^2/C^2) * 1/9e^2) / (0.71 x 10^-15 m)^2

Now, we can calculate the value of F using a calculator or computer program. The result will be in Newtons (N), which represents the magnitude of the electrostatic force exerted by the down quarks on each other when they are separated by a distance of 0.71 fm.