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2poles are placed vertically in a pool.one third of the longer pole and two fifths of the shorter pole is under water.if the difference in leng 42 cm,how deep is the pool?th

  • math -

    L-S=42
    now water height is the same, so
    1/3 L = 2/5 S

    L-S=42
    5L-6S=0

    solve.

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