What force do the blades of a 4200 kg helicopter exert on the air when the helicopter is dropping at 23 m/s with speed decreasing at 3.7 m/s^2?

To find the force exerted by the blades of a helicopter on the air, we'll need to use Newton's second law of motion.

Newton's second law states that the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, the mass of the helicopter is given as 4200 kg, and the acceleration is the rate at which the speed is decreasing, which is -3.7 m/s² (negative because it's a deceleration).

So, the force exerted by the helicopter on the air can be found using the formula:

Force = mass * acceleration

Force = 4200 kg * (-3.7 m/s²)

Now, we can compute the force:

Force = -15,540 N

Therefore, the blades of the helicopter exert a force of -15,540 Newtons on the air when the helicopter is dropping at 23 m/s with a speed decreasing at 3.7 m/s².