How much heat is required to bring 1.0kg of water from 25 degrees celsius to 99 degrees celsius?
q = mass x specific heat H2O x (Tfinal-Tinitial)
To determine the amount of heat required to raise the temperature of water, you can use the formula:
Q = mcΔT,
where Q is the amount of heat, m is the mass of the substance (water in this case), c is the specific heat capacity of water, and ΔT is the change in temperature.
First, let's find the specific heat capacity of water. The specific heat capacity of water is approximately 4.186 J/g°C, or 4186 J/kg°C.
Next, we need to determine the change in temperature, which is given by:
ΔT = final temperature - initial temperature.
In this case, the final temperature is 99°C, and the initial temperature is 25°C. So,
ΔT = 99°C - 25°C = 74°C.
Now we can substitute the values into the formula:
Q = (1.0 kg) * (4186 J/kg°C) * (74°C).
Calculating this expression, we find that:
Q = 309,844 J.
Therefore, it would require approximately 309,844 J of heat to raise the temperature of 1.0 kg of water from 25°C to 99°C.