what is the slope-intercept form of 16x-y=8
16 x - y = 8 Add y to both sides
16 x - y + y = 8 + y
16 x = 8 + y Subtract 8 to both sides
16 x - 8 = 8 + y - 8
16 x - 8 = y
y = 16 x - 8
To find the slope-intercept form of a linear equation, you need to isolate the variable y on one side of the equation.
The given equation is 16x - y = 8.
To isolate y, we need to move the 16x term to the other side of the equation by subtracting 16x from both sides:
- y = -16x + 8.
Next, we need to rewrite the equation in slope-intercept form, y = mx + b.
In this form, m represents the slope of the line, and b represents the y-intercept (the point where the line crosses the y-axis).
By rearranging the terms, the equation becomes:
y = -16x + 8.
Hence, the slope-intercept form of the equation 16x - y = 8 is y = -16x + 8.
To find the slope-intercept form of a linear equation, we need to rearrange the equation in the form of "y = mx + b", where "m" represents the slope of the line and "b" represents the y-intercept.
Let's start with the given equation:
16x - y = 8
To isolate the y-term, we need to move the 16x term to the right side of the equation. We can do this by subtracting 16x from both sides:
-y = -16x + 8
Now, to make the coefficient of y positive, we multiply both sides of the equation by -1:
y = 16x - 8
Therefore, the slope-intercept form of the equation 16x - y = 8 is y = 16x - 8.