Graph the linear equation 3y = 6x +3. Then rewrite the equation using the form y = ax + b.

Thanking you

To rewrte it in y=mx+b form, you do this :

3y=6x+3

divide both sides by 3 so it would be

y= 2x+1

To graph the linear equation 3y = 6x + 3, we need to rearrange it into the form y = ax + b.

Step 1: Starting with the given equation, 3y = 6x + 3, divide both sides by 3 to isolate y:

(3y)/3 = (6x + 3)/3
y = 2x + 1

Now, we have rewritten the equation in the form y = ax + b, where a = 2 and b = 1.

To graph this equation, we can use the slope-intercept form, y = mx + c, where m is the slope and c is the y-intercept.

In our case, the slope (m) is 2 and the y-intercept (c) is 1. This means the line will have a slope of 2 (rise of 2 units for every run of 1 unit) and intersect the y-axis at the point (0, 1).

Step 2: Plot the y-intercept:
On the coordinate plane, locate the point (0, 1). This is the y-intercept, meaning the line crosses the y-axis at y = 1.

Step 3: Use the slope to find additional points:
From the y-intercept (0, 1), use the slope of 2 to find additional points. Since the slope is 2, we can either go up 2 units and right 1 unit or down 2 units and left 1 unit to find the next point.

For example, starting from (0, 1), if we go up 2 units and right 1 unit, we get the point (1, 3). If we continue this pattern, we can find other points such as (2, 5), (3, 7), and so on.

Step 4: Plot the points and draw the line:
Plot the points (0, 1), (1, 3), (2, 5), (3, 7), and any other points you find using the same pattern. Then, connect the points with a straight line. This line represents the graph of the equation y = 2x + 1.

I hope this helps! Let me know if you have any further questions.