calculus

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a curve is such that dy/dx = x^2 - 1
Show that no tagent to this curve is parallel to the line with equation
3x + 2y - 4 = 0

  • calculus -

    slope of the given line is -3/2

    so x^2 - 1 must be equal to -3/2

    x^2 - 1 = -3/2
    x^2 = 1 - 3/2 = -1/2
    BUT a square of a real number cannot be negative, so no solution,
    so no such tangent

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