calculus
posted by yuen .
a curve is such that dy/dx = x^2  1
Show that no tagent to this curve is parallel to the line with equation
3x + 2y  4 = 0

slope of the given line is 3/2
so x^2  1 must be equal to 3/2
x^2  1 = 3/2
x^2 = 1  3/2 = 1/2
BUT a square of a real number cannot be negative, so no solution,
so no such tangent
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