An 849 g mass is attached to a pulley and
a 9 N weight is attached to a thin massless
cord, as shown below.
.5
849 g
9 N
T
What is the tension T? The pulley is massless and frictionless. The acceleration of gravity is 9.8 m/s
2
.
Answer in units of N
To find the tension, T, in the thin massless cord, we need to consider the forces acting on the system.
In this case, we have two forces - the weight of the 849 g mass (which is equivalent to its mass multiplied by the acceleration due to gravity) and the 9 N weight attached to the cord.
Let's break down the forces:
1. Weight of the 849 g mass:
The weight can be calculated using the equation: weight = mass x acceleration due to gravity. Substituting the values, we get:
weight = 0.849 kg x 9.8 m/s^2.
2. The 9 N weight attached to the cord:
Here, the force is already given as 9 N.
Since the pulley is massless and frictionless, there are no additional forces to consider.
Now, let's analyze the system:
The 849 g mass is being pulled downward by its weight, causing tension in the cord. The 9 N weight is also pulling the cord downwards. The cord transmits this tension to the 849 g mass, resulting in equilibrium.
Since the system is in equilibrium, the tension T in the cord will be equal to the combined weight of the 849 g mass and the 9 N weight.
Adding the forces together, we get:
T = weight of 849 g mass + 9 N weight.
Now, let's calculate the tension T:
T = (0.849 kg x 9.8 m/s^2) + 9 N.
By multiplying and adding the values, we find:
T = 8.3122 N + 9 N.
Simplifying further, we get:
T = 17.3122 N.
Therefore, the tension T in the cord is equal to 17.3122 N.