knowing that one mole of KHP, C8H5O4K, reacts with one mole of NaOH, what mass of KHP is required to neutralized 30.0mL of the 0.10 M NaOH solution?

30mL of .1M NaOH has .03*.1 = .003 moles NaOH.

so, it will take .003 moles of KHP to react with it. Convert moles to grams to get the mass.

To find the mass of KHP required to neutralize the given volume of NaOH solution, we can follow these steps:

Step 1: Determine the number of moles of NaOH solution.
The volume of the NaOH solution is given as 30.0 mL, and its concentration is 0.10 M (moles/L). We can convert the volume into liters by dividing it by 1000:
30.0 mL / 1000 = 0.030 L

Then, we can calculate the number of moles using the formula:
Moles = Concentration x Volume
Moles = 0.10 M x 0.030 L

Step 2: Determine the molar ratio between KHP and NaOH.
According to the given information, one mole of KHP reacts with one mole of NaOH. Therefore, the molar ratio is 1:1.

Step 3: Calculate the number of moles of KHP required.
Since the molar ratio is 1:1, the number of moles of KHP required will be the same as the number of moles of NaOH. So, the number of moles of KHP is also:
0.10 M x 0.030 L

Step 4: Convert moles of KHP to grams.
The molar mass of KHP (C8H5O4K) can be found by summing the atomic masses:

C = 12.01 g/mol
H = 1.01 g/mol (x 5 as there are 5 hydrogen atoms in KHP)
O = 16.00 g/mol (x 4 as there are 4 oxygen atoms in KHP)
K = 39.10 g/mol
Total molar mass = (12.01 x 8) + (1.01 x 5) + (16.00 x 4) + 39.10

Finally, multiply the number of moles of KHP by its molar mass to obtain the mass of KHP required.

Note: The molar mass of KHP may vary slightly depending on the degree of precision required.

I hope this explanation helps you understand how to solve the problem!