what is the formula weight for CuSO4 5H2O?
Look up each element and add multiples of their atomic weights. What do you get?
For example, CaCl2 has weight 40.08+2(35.45) = 110.98
I got the answer of 249.6
Is that correct? Thanks for your help!
That's what I got. Nice work.
To find the formula weight of CuSO4 · 5H2O (copper(II) sulfate pentahydrate), we need to calculate the sum of the atomic weights of all the elements in the compound.
First, let's find the atomic weights of the individual elements:
- Atomic weight of Cu (copper) = 63.55 g/mol
- Atomic weight of S (sulfur) = 32.07 g/mol
- Atomic weight of O (oxygen) = 16.00 g/mol
- Atomic weight of H (hydrogen) = 1.01 g/mol
Since there are 5 hydrogen atoms in the compound, we multiply the atomic weight of hydrogen by 5.
Next, let's calculate the formula weight:
Formula weight of CuSO4 · 5H2O =
(Atomic weight of Cu) + (Atomic weight of S) + (4 × Atomic weight of O) + (5 × Atomic weight of H) + (5 × (Atomic weight of O + Atomic weight of H))
= 63.55 + 32.07 + (4 × 16.00) + (5 × 1.01) + (5 × (16.00 + 1.01))
Calculating this expression will give you the formula weight for CuSO4 · 5H2O.