find the perimeter of a triangle whose vertices are the followinf specified points in the plane?
(9,-1)(-9,7)and(4,3)
The sides have lengths
√(18^2 + 8^2) = √388
√(5^2 + 4^2) = √41
√(13^2 + 4^2) = √185
Not much can be done to simplify that, so just add them up. The total is approx. 39.7
find the perimeter of a triangle whose vertices are the followinf specified points in the plane?
(-5,4)(2,9)and(10,-5)
find the perimeter of a triangle whose vertices are the followinf specified points in the plane?
(-5,4)(2,9)and(10,-5)
To find the perimeter of a triangle, you need to calculate the distance between each pair of vertices and then add them together.
Let's calculate the distances between the given points:
1. Distance between (9, -1) and (-9, 7):
- To find the distance between two points (x1, y1) and (x2, y2), you can use the distance formula: d = sqrt((x2 - x1)^2 + (y2 - y1)^2)
- In this case, the coordinates of the first point are (x1, y1) = (9, -1) and the coordinates of the second point are (x2, y2) = (-9, 7)
- Plugging in the values into the distance formula, we get d = sqrt((-9 - 9)^2 + (7 - (-1))^2) = sqrt((-18)^2 + (8)^2) = sqrt(324 + 64) = sqrt(388) = 19.697
2. Distance between (-9, 7) and (4, 3):
- Using the same formula, we get d = sqrt((4 - (-9))^2 + (3 - 7)^2) = sqrt((13)^2 + (-4)^2) = sqrt(169 + 16) = sqrt(185) = 13.601
3. Distance between (4, 3) and (9, -1):
- Again, applying the distance formula, we have d = sqrt((9 - 4)^2 + (-1 - 3)^2) = sqrt((5)^2 + (-4)^2) = sqrt(25 + 16) = sqrt(41) = 6.403
Finally, to get the perimeter of the triangle, we add the three distances:
Perimeter = 19.697 + 13.601 + 6.403 = 39.701
Therefore, the perimeter of the triangle with vertices (9, -1), (-9, 7), and (4, 3) is approximately 39.701 units.