posted by Emmy .
i am having problems understanding.... i don't know how to put it so i will just put what the problem is
Write the slope-intercept form of an equation of the line that passes through the given point and is parallel to the graph of each equation
13. (2,-7) y= x-2
i know that 2 and -7 is the slope to the line that i have to get the new line to be parallel to it.... if that makes sence... but please help!!!
in the y-intercept slope form
y = mx + b
the slope is m and the y-intercept is b
(2, -7) is a point and tells you nothing about the slope.
so the given line is y = x-2
or y = 1x - 2, so you know the slope must be 1, since the two lines are to be parallel
and the new line must look like
y = 1x + b, where only the y-intercept or the b would have changed
Now we plug in our new point (2,-7)
-7 = 1(2) + b
b = -9
your new equation parallel to the old one is
y = x - 9
ohhhhhh now i see ok can i do one and could you tell me if im right??
will be here for another 15 minutes
y=2x-5 <--- is this right?
yep. to check, just plug in (2,-1) and see whether it satisfies the equation. Since 2(2)-5 = -1, you're right on.
thank you sooooo much!!!!