Algebra
posted by Emmy .
i am having problems understanding.... i don't know how to put it so i will just put what the problem is
Write the slopeintercept form of an equation of the line that passes through the given point and is parallel to the graph of each equation
13. (2,7) y= x2
i know that 2 and 7 is the slope to the line that i have to get the new line to be parallel to it.... if that makes sence... but please help!!!

in the yintercept slope form
y = mx + b
the slope is m and the yintercept is b
(2, 7) is a point and tells you nothing about the slope.
so the given line is y = x2
or y = 1x  2, so you know the slope must be 1, since the two lines are to be parallel
and the new line must look like
y = 1x + b, where only the yintercept or the b would have changed
Now we plug in our new point (2,7)
7 = 1(2) + b
b = 9
your new equation parallel to the old one is
y = x  9 
ohhhhhh now i see ok can i do one and could you tell me if im right??

will be here for another 15 minutes

(2,1) y=2x+2

y=2x+b
1=2(2)+b
1=4+5

y=2x5 < is this right? 
yep. to check, just plug in (2,1) and see whether it satisfies the equation. Since 2(2)5 = 1, you're right on.

thank you sooooo much!!!!