physics help i still dont get it
posted by justin .
A picture of width 43.0 cm, weighing 52.0 N, hangs from a nail by means of flexible wire attached to the sides of the picture frame. The midpoint of the wire passes over the nail, which is 2.50 cm higher than the points where the wire is attached to the frame. Find the tension in the wire.

sinα =2,5/sqrt{2.5²+(43/2)²}
m•g=2•T•sinα
T=m•g/2•sinα 
ill try it but i have no idea how you get the angle appreciate it

sinα =2,5/sqrt{2.5²+(43/2)²} =0.116
m•g=2•T•sinα
T=m•g/2•sinα =52/2•0.116 =225 N 
Thank you so much but its just upsetting me i cant figure it out

i forgot to divide the sqrt by 2.5 to get .116 sorry but thank u
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