A current of 60 mA passes through a loudspeaker of resistance 6 Ω. What is the potential difference across the resistance of the loudspeaker?
36.0 V
10.0 V
0.36 V
0.10 V
Answer B seems like it would be the obvious answer..
V = i R
= 60*10^-3 * 6
= 360 * 10^-3 = .36
To find the potential difference across the resistance of the loudspeaker, you can use Ohm's Law, which states that V = I * R, where V is the potential difference, I is the current, and R is the resistance.
In this case, the current (I) is given as 60 mA, which can be converted to amperes by dividing by 1000: 60 mA = 0.06 A.
The resistance (R) of the loudspeaker is given as 6 Ω.
Now, plug these values into Ohm's Law equation:
V = I * R
V = 0.06 A * 6 Ω
V = 0.36 V
Therefore, the potential difference across the resistance of the loudspeaker is 0.36 V, which corresponds to answer C.
To find the potential difference (V) across the resistance of the loudspeaker, you can use Ohm's Law, which states that V = I * R.
In this case, the current (I) passing through the loudspeaker is given as 60 mA, which is equal to 0.060 A. The resistance (R) of the loudspeaker is given as 6 Ω.
Now, substitute the values into the formula: V = 0.060 A * 6 Ω.
The product of 0.060 A and 6 Ω is 0.36 V.
Therefore, the correct answer is 0.36 V. Option C is the correct answer.