posted by Michelle .
A military helicopter on a training mission is flying horizontally at a speed of 60.0 m/s and accidentally drops a bomb (fortunately not armed) at an elevation of 350 m. You can ignore air resistance.
Find the horizontal and vertical components of its velocity just before it strikes the earth.
a) d = 1/2(a x t^2); rewrite to solve for t:
t = sqrt(2 x d / a) = sqrt( 2 x 350 / 9.8) = 8.45 seconds
b) horiz distance = v x t = 60 x 8.45 = 507 meters
c) bombs horizontal component of velocity doesn't change, neglecting air resistance = 60.0 m/s.
d) the helicopter is directly over the bomb if no air resistance