A bullet is fired straight up from a gun with a muzzle velocity of 312 m/s. Neglecting air resistance, what will be its displacement after 1.4 s?
30
To find the displacement, we need to use the equation of motion for an object in free fall, considering the initial velocity and time. The equation can be written as:
Displacement = Initial velocity * Time + (1/2) * acceleration * (Time^2)
In this case, the initial velocity is 312 m/s, the time is 1.4 s, and the acceleration is the acceleration due to gravity, which is approximately 9.8 m/s^2.
Let's now substitute these values into the equation:
Displacement = 312 m/s * 1.4 s + (1/2) * 9.8 m/s^2 * (1.4 s)^2
Simplifying the equation:
Displacement = 436.8 m + 9.8 m/s^2 * 1.96 s^2
Displacement = 436.8 m + 19.16 m
Displacement = 455.96 m
Therefore, the displacement of the bullet after 1.4 seconds will be approximately 455.96 meters.