Calculate the theoretical yield in moles of Fe(C5H7O2)3 for this experiment. Record this number on your data sheet.
Calculate the theoretical yield in g Fe(C5H7O2)3 (GMM: 353.18g mol^-1), for this experiment. Record this number on your data sheet.
I really need help on these two questions. I have no idea on how to do it. Please somebody help me to solve these problems.
I don't know the equation and I have no idea what C5H7O2 is; however, on a best guess I can write an abbreviated equation as
Fe^3+ + 3C5H10O2==> Fe(C6H7O2)3
a. You provided no data; therefore, I can't calculate a theoretical yield. Again, my best guess is you have grams Fe or grams of the other component.
mols theoretical yield = (1/3)*mols C5H?O2 component. If it's Fe you have, then mols theoretical yield = same as mols Fe.
b. grams = mols x molar mass. You have mols fropm part a and you have molar mass in the problem. Solve away.
To calculate the theoretical yield in moles of Fe(C5H7O2)3 for the experiment, we need to know the amount of reactants and the balanced chemical equation.
Please provide the balanced chemical equation and the amounts of reactants used in the experiment.
To calculate the theoretical yield in moles of Fe(C5H7O2)3, we need to know the starting amount or number of moles of the reactants involved in the experiment. If you have this information, you can use stoichiometry to find the theoretical yield.
Stoichiometry is based on the balanced chemical equation for the reaction between the reactants and products. It tells us the ratios in which the reactants are consumed and the products are produced. Without the balanced chemical equation or additional information about the experiment, we cannot determine the theoretical yield.
Similarly, to calculate the theoretical yield in grams of Fe(C5H7O2)3, we need to know the starting amount or mass of the reactants. If you have this information, you can use stoichiometry and the molar mass of Fe(C5H7O2)3 to find the theoretical yield.
The molar mass of Fe(C5H7O2)3 is given as 353.18 g mol^-1, so for every mole of Fe(C5H7O2)3, there will be 353.18 grams.
Again, without the necessary information, it is not possible to calculate the theoretical yield.