College Algebra
posted by Randi .
An arrow is launched upward with a velocity of 54 feet per second from the top of a 75 foot building. What is the maximum height attained by the arrow in feet?

from your information, the height h is
h = 16t^2 + 54t +75 , where t is in seconds and h is in feet
dh/dt = 32t + 54
= 0 for a max h
32t = 54
t = 54/32 = 27/16 > time it took to reach max height = 16(27/16)^2 + 54(27/16) + 75
= 120.56 ft
h = 16(
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