10.0 g of KCl and 18.5 g of CaCl2 were dissolved in 500 mL of water. How many mL of 1.57 M AgNO3 solution would be required to precipitate all Cl- from the solution?

first, identify the reactions:

KCl + AgNO3 = KNO3 + AgCl
CaCl2 + 2AgNO3 = Ca(NO3)2 + 2AgCl

convert grams to moles for KCl and CaCl2 to get total moles of Cl involved

Each mole of Cl requires one mole of AgNO3 to react.

divide that no. of moles by 1.57 to get liters of AgNO3 needed