Math

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In triangle XYZ, |XY|= 8 cm and |YZ|=6m.
The area of triangle XYZ is 12cm^2. The |<PQR|= 30 degrees, 150 degrees.
Find the two possible |XZ|

  • math - eh? -

    Given XYZ, WTF is PQR?

  • Math -

    I mean |<XYZ|

  • Math -

    XZ^2 = 6^2 + 8^2 - 2*6*8cosY
    cosY is either sqrt(3)/2 or -sqrt(3)/2

    XZ^2 = 100-96*.866
    XZ = 4.1
    or
    XZ^2 = 100+96*.866
    XZ = 13.5

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