If a seagull flies to a height of 22.5 meters, how long will the clam take to fall? The acceleration of gravity is 9.8m/s. answer in units of sec

x = 1/2 * g * t^2

22.5 = 0.5 * 9.8 * t^2

Solve for the time

To determine the time it will take for the clam to fall from a height of 22.5 meters, we can use the equations of motion and apply the laws of gravity.

The equation that relates the height, acceleration, and time is:

h = (1/2) * g * t^2

Where:
h is the height (22.5 meters)
g is the acceleration due to gravity (9.8 m/s^2)
t is the time it takes for the clam to fall

Rearranging the equation, we have:

t^2 = (2 * h) / g

Substituting the given values, we get:

t^2 = (2 * 22.5) / 9.8

Simplifying further:

t^2 = 45 / 9.8

t^2 = 4.5918

To find the value of t, we take the square root of both sides:

t ≈ √4.5918

t ≈ 2.141 seconds (rounded to three decimal places)

Therefore, the clam will take approximately 2.141 seconds to fall from a height of 22.5 meters.