calculate the morality of THE H2SO4 solution for each of the three runs. do the three values agree closely together with each other.
Part A.
Titration 1
volume of unknown acid =20ml
initial buret reading of NaOH =0.5 ml
final buret reading of NaOH=10.0ml
Titartion 2
volume of unknown acid =20ml
initial buret reading of NaOH=18.0.ml
final buret reading of NaOH = 36.0ml
titartion 3
volume of unknown acid 20ml
intinal reading of NaOH =7.3
final buret reading of NaOH 25.ml
Several things I should mention.
It's molarity, not morality. I don't know if these solution are moral or not. :-).
Second, you don't list a molarity of the NaOH. You must have that in order to calculate the molarity of the unknown acid.
volume NaOH = final reading-initial reading.
mols NaOH = M(not listed) x L = ?
mols acid = same as mols NaOH
Then M acid = mols acid/L acid.
THOSE ARE THE RESULT IN MY LAB AND I HAVE TO CALCULATE THE MOLARITY OF THE THREE TITRATIONS. HOW DO I FIND THE VALUES IN THE H2SO4
My first response was in error where I said mols H2SO4 =same as mols NaOH. That isn't correct.
Here are the correct instructions.
H2SO4 + 2NaOH ==> 2H2O x Na2SO4
volume NaOH = final reading - initial reading.
mols NaOH = M NaOH (M not listed in the post) x x L NaOH.
Convert to mols H2SO4.
mols H2SO4 = 1/2 x mols NaOH
Then M H2SO4 = mols H2SO4/L H2SO4.
To calculate the molarity of the H2SO4 solution for each of the three runs, we need to use the concept of titration. Titration is a method used to determine the concentration of an unknown solution by reacting it with a known concentration solution.
In this case, NaOH (sodium hydroxide) is the known concentration solution, and H2SO4 (sulfuric acid) is the unknown concentration solution.
The equation for the reaction between NaOH and H2SO4 is:
2NaOH + H2SO4 -> Na2SO4 + 2H2O
To calculate the molarity of H2SO4, we can use the formula:
Molarity (M) = (Volume of NaOH x Molarity of NaOH) / Volume of H2SO4
Now, let's calculate the molarity for each of the three runs:
Part A:
Titration 1:
Volume of NaOH = Final buret reading - Initial buret reading = 10.0 ml - 0.5 ml = 9.5 ml
Molarity of NaOH (given) = ??? (not provided in the question)
Volume of H2SO4 = 20 ml
Without the molarity of NaOH, we cannot calculate the molarity of H2SO4 for this run.
Titration 2:
Volume of NaOH = Final buret reading - Initial buret reading = 36.0 ml - 18.0 ml = 18.0 ml
Molarity of NaOH (given) = ??? (not provided in the question)
Volume of H2SO4 = 20 ml
Without the molarity of NaOH, we cannot calculate the molarity of H2SO4 for this run.
Titration 3:
Volume of NaOH = Final buret reading - Initial buret reading = 25.0 ml - 7.3 ml = 17.7 ml
Molarity of NaOH (given) = ??? (not provided in the question)
Volume of H2SO4 = 20 ml
Without the molarity of NaOH, we cannot calculate the molarity of H2SO4 for this run.
In conclusion, we cannot calculate the molarity of the H2SO4 solution for each of the three runs because the molarity of NaOH is not provided for any of the titrations. Therefore, we cannot determine whether the three values agree closely with each other.