Identify the vertex and the axis of symmetry of the graph functio
y=3(x+2)^2-3
Could someone please help me
as you should know, the parabola
y = a(x-h)^2 + k
has vertex at (h,k) and axis x=h.
So, just read them off from your equation. Just be sure to make it fir the format exactly. Your equation is
y = 2(x-(-2)) + (-3), so h = -2 and k = -3
vertex: (-2,-3)
axis: x = -2
Oh thank you for explaining
Sure! I'd be happy to help you with that.
To identify the vertex and axis of symmetry of the given quadratic function, y = 3(x + 2)^2 - 3, we can use the standard form of the quadratic equation, which is y = a(x - h)^2 + k. In this form, (h, k) represents the coordinates of the vertex.
Comparing the given function with the standard form, we can see that a = 3, h = -2, and k = -3.
Now, to find the vertex, we substitute the values of h and k into the coordinates (h, k):
Vertex = (-2, -3)
The x-coordinate of the vertex represents the axis of symmetry. So, in this case, the axis of symmetry is x = -2.
Therefore, the vertex of the graph is (-2, -3), and the axis of symmetry is x = -2.