math
posted by Anonymous .
Rewrite the expression as an algebraic expresion in x:
tan(sin−1x)=

sorry I meant tan(sin^1 x)=

sin^1 x is angle in a right  angled triangle where the opposite side is x and the hypotenuse is 1
let that angle be Ø
so really sin^1 x > sinØ = x/1
so the third side is √(1  x^2)
then tan(sin^1 x)
= tan Ø
= x/√(1x^2)
check:
e.g. let x = .5
then sin^1 (.5) = π/6
and tan(π/6) = .57735
according to my answer
tan(sin^1 (.5)) = .5/√(1.25) = .57735
all looks good.
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