A block (weight= 10kg) is sitting on a surface with friction (coefficient= 0.5). A force (push) is applied to the end of the block, 35 degrees below the horizontal. Calculate the magnitude of the force to move the block.
y: N=mg+F•sinα
x: F•cosα=F(fr) =μ•N=μ•( mg+F•sinα)
F=μ•m•g/(cosα-μ•sinα)
To calculate the magnitude of the force required to move the block, we need to consider the force of friction acting on the block. The force of friction can be calculated using the equation F_friction = coefficient_of_friction * normal_force.
First, let's determine the normal force acting on the block. The normal force is the force exerted by a surface to support the weight of an object resting on it and acts perpendicular to the surface.
In this case, the weight of the block is given as 10 kg. The weight is equal to the force due to gravity acting on an object, which is calculated as weight = mass * acceleration due to gravity.
The acceleration due to gravity is approximately 9.8 m/s^2. Therefore, the weight of the block is 10 kg * 9.8 m/s^2 = 98 N.
Since the block is sitting on a horizontal surface, the normal force is equal to the weight of the block, so the normal force is 98 N.
Now, we can calculate the force of friction. The coefficient of friction is 0.5, as given in the question.
F_friction = 0.5 * 98 N = 49 N.
The force of friction opposes the applied force and needs to be overcome to move the block. Therefore, the magnitude of the force required to move the block is equal to the force of friction, which is 49 N.