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A football is kicked 66.6 meters. If the ball is in the air 5.39 s, with what initial velocity was it kicked?

  • physics -

    Tr = Tf = 5.39/2 = 2.695 s.
    Tr = Rise time.
    Tf = Fall time.

    Y = Yo + gt.
    Y = 0 + 9.8*2.695 = 26.4 m/s = Final velocity when falling = Initial velocity
    (Yo)when rising. Y=Ver. componenttg of velocity.

    Range = Xo*(Tr+Tf) = 66.6 m.
    Xo*(5.39) = 66.6
    Xo = 12.36 m/s. = Hor. component of
    initial velocity.

    tanA = Yo/Xo = 26.4/12.36 = 2.13592
    A = 64.9o.
    Vo=Xo/cosA=12.36/cos64.9=29.2 m/s@64.9o
    = Initial velocity.

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