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An airplane flying at 550 miles per hour has a bearing of 53°. After flying for 2.5 hours, how far north and how far east will the plane have traveled from its point of departure?

I'm having a REALLY hard time with this one. I don't know what I'm doing wrong. Can someone walk me through this?

  • TRIG -

    If you are using standard notation, then a bearing of 53° would be 53° clockwise from North
    make a sketch.
    Start the plane at the origin, then draw a line 53° form the y-axis (NOrth) and make it 2.5(550) or 1375 miles long. Complete the right-angled triangle, whose base angle will be 37°

    distance north:
    y/1375 = sin37
    y = 827.5 miles
    distance east:
    x/1375 = cos 37
    x = 1098.1 miles

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