We will calculate the amount of acid to use in each titration. Assume that you are using 0.0512 M NaOH(aq). A good volume of NaOH(aq) to use per titration is 15mL. From this molarity and volume, the moles of NaOH can be calculated. Since the unknown acid is monoprotic, this aso equals the number of moles of acid to use. a typical molar mass for an unknown acid in this experiment is 380g/mol. Using this molar mass, calculate the mass (in grams) of unknown aid you should use per titraton

To calculate the mass of unknown acid needed per titration, we need to follow a step-by-step approach:

Step 1: Calculate the moles of NaOH used in each titration.
Given: Molarity of NaOH = 0.0512 M
Volume of NaOH = 15 mL = 0.015 L

The moles of NaOH can be calculated using the formula:
moles = molarity × volume
moles of NaOH = 0.0512 M × 0.015 L

Step 2: Since the unknown acid is monoprotic, the moles of NaOH used will be equal to the moles of acid used in each titration.

Step 3: Calculate the mass of the unknown acid used.
Given: Molar mass of unknown acid = 380 g/mol

The mass of the unknown acid in grams can be calculated using the formula:
mass = moles × molar mass
mass of unknown acid = moles of acid × molar mass

Now, substituting the values obtained from Step 1 and Step 3:
mass of unknown acid = (0.0512 M × 0.015 L) × 380 g/mol

Calculating this expression will give you the mass of unknown acid needed per titration.