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How much heat is necessary to change 500g of ice at-10 celsius to water at 20 celsius?

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You will need to know these numbers:

specific heat of ice = 2.09 J/g·°C specific heat of water = 4.18 J/g·°C
heat of fusion (melting) of ice: 334 J/g

Total Heat required =
Q = energy reqd to heat 500 g ice from -10 to 0 C
+ energy reqd. to melt 500 g of ice @ 0 C
+ energy reqd. to heat 500 g water from 0 to 20 C.
= 500[10*2.09 + 334 + 20*4.18]
= ___ Joules

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