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What is the concentration of Cu2+ in a solution that is 0.10 M Cu(NH3)4^2+? (Kf = 1.2 x 10^12)

The answer is 8.0 x 10^-4

How do I solve the problem to get the answer

  • Chemistry -

    Write the equation and set up an ICE chart.
    .........Cu^2+ + 4NH3 ==> Cu(NH3)4^2+

    Kf = 1.2E12 = [Cu(NH3)4^2+]/(x)(4x)^4
    Solve for x.
    8E-4 M is correct.

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