Math

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ÚABC ~= ÚACB
BD perpendicular AC
The sum fo the three angles in any triangle is 180 degree.

Prove: mÚCBD = 1/2 mÚBAC

  • Math -

    angle ABC ~= angle ACB
    BD perpendicular AC
    The sum fo the three angles in any triangle is 180 degree.

    Prove: mangle CBD = 1/2 mangle BAC

  • Math -

    let angle CBD = a

    in trianagle ABC:
    2x + y = 180

    in triangle BCD
    a + x = 90 or 2a + 2x = 180

    then 2a + 2x = 2x + y , both equal to 180
    2a = y
    a = (1/2y
    or
    angle CBD = (1/2) angle BAC

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