precal
posted by ladybug .
find the equation of a line that is perpendicular to the line y=1/6x+7 and contains the point (5,0)
y=
(Type your answer in slope intercept form)

slope has to be 6 because it is 1/(1/6)
note m' = 1/m
so of form
y = 6 x + b
put the point in
0 = 6 (5) + b
so
b = 30
then
y = 6 x 30