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Integrate Sin(rootx) wrt x

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    ∫sin√x dx

    let
    u = √x
    du = 1/(2√x) dx
    dx = 2√x du = 2u du

    ∫sin√x dx = ∫sinu (2u du)
    = 2∫u sinu du

    now use integration by parts to get

    2sinu - 2u cosu

    and convert back to x's

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