maths
posted by vikash .
Find the Cartesian form of the equation, r3 = 3r cosØ

I will assume you meant
r^3 = 3r cosØ
Use: r^2 = x^2 + y^2 and x/r = cosØ
so if rcosØ = x
then 3rcosØ = 3x
and r^3 = r^2 r
= (x^2 + y^2)(x^2+y^2^(1/2)
= (x^2 + y^2)^(3/2)
r^3 + 3rcosØ > (x^2 + y^2)^(3/2) = 3x
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