r^3 = 3r cosØ Use: r^2 = x^2 + y^2 and x/r = cosØ so if rcosØ = x then 3rcosØ = 3x and r^3 = r^2 r = (x^2 + y^2)(x^2+y^2^(1/2) = (x^2 + y^2)^(3/2) r^3 + 3rcosØ ---> (x^2 + y^2)^(3/2) = 3x
You can ask a new question or answer this question.