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A rocket moves upward, starting from rest with an acceleration of 32.0 m/s2 for 3.27 s. It runs out of fuel at the end of the 3.27 s but does not stop. How high does it rise above the ground?

  • physics -

    work this in two parts.
    launch vf(at end of burn)=a*t
    heightatendofburn;1/2 a t^2

    Now the second part, start at the height above, with a vi = vf of the burn.

    find the max height. at the top, vf=0
    vf^2=0=vi^2+2ah where g=-9.8m/s^2, solve for h. Add that h to the heightattheendof burn

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