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Calculate the heat capacity of a calorimeter if th ecombustion of 4.665 g of benzoic acid led to an increase in temperature of 7.148 C
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Calculate the heat capacity of a calorimeter if th ecombustion of 4.665 g of benzoic acid led to an increase in temperature of
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im confused on how to get the grams to KJ.
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Calculate the heat capacity of a calorimeter if th ecombustion of 4.665 g of benzoic acid led to an increase in temperature of
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im confused with how to get KJ??
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The combustion of 0.1572 g benzoic acid increases the temperature of a bomb calorimeter by 2.52°C. Calculate the heat capacity
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Sorry I didn't mean to repost this!
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The combustion of 0.1572 g benzoic acid increases the temperature of a bomb calorimeter by 2.52°C. Calculate the heat capacity
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are you certain about the mass of benzoic acid? .1572g is a very small amount. heatenergy=
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The combustion of 0.1619 g benzoic acid increases the temperature of a bomb calorimeter by 2.77°C. Calculate the heat capacity
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qcal x delta T = 0.1619g*26.43 kJ/g Solve for qcal. qvanillin = qcal x delta T qvanillin/0.1510 =
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The combustion of 0.1583 g benzoic acid increases the temperature of a bomb calorimeter by 2.93°C. Calculate the heat capacity
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See http://www.jiskha.com/display.cgi?id=1321212060
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The enthalpy of combustion of benzoic acid (C6H5CO2H) is -3228 kJ/mol. The burning of 1.698 g of benzoic acid in a calorimeter
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To find the heat capacity of the calorimeter, we can use the formula: q = mcΔT where q is the heat
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The enthalpy of combustion of benzoic acid (C6H5CO2H) is –3228 kJ/mol. The burning of 1.698 g of benzoic acid in a calorimeter
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mols benzoic acid = grams/molar mass = ? Then q = mols benz acid x Ccal(delta T) q is +3238 kJ.
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the enthalpy of combustion of benzoic acid C6H5COOH, which is used to calibrate calorimeters usualmete is -3227 kJ mol-1.
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Convert 1.453 g benzoic acid to mols. mols = grams/molar mass = ? q = Ccal x (Tfinal-Tinitial)
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21.90 kJ/g x 0.1182 g = ?q = energy obtained by combusting salicylic acid.
Then calculate the heat capacity of the calorimeter.
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I see my response to one of your earlier question but no question
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