If 100J are added ti 20g of water at 30degrees Celsius, what will be the final temperature of the water

q = mass H2O x specific heat H2O x (Tfinal-Tinitial)

Substitute and solve for Tf.

-2508

To determine the final temperature of the water, we can use the specific heat formula:

Q = mcΔT

where:
Q is the heat transferred to the water (in Joules)
m is the mass of the water (in grams)
c is the specific heat capacity of water (about 4.18 J/g°C)
ΔT is the change in temperature

In this case, we know that 100J of heat is added to 20g of water at 30°C. Let's calculate the change in temperature (ΔT) using the formula:

ΔT = Q / (mc)

Substituting the known values:
ΔT = 100J / (20g * 4.18 J/g°C)

Now, we can calculate the final temperature by adding the change in temperature to the initial temperature:

Final temperature = Initial temperature + ΔT

Initial temperature = 30°C

Substituting the values into the formula:

Final temperature = 30°C + ΔT

Now let's calculate ΔT and find the final temperature.