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Tarzan swings on a 34.0-m-long vine initially inclined at an angle of 33.0° with the vertical.
(a) What is his speed at the bottom of the swing if he starts from rest?
m/s

(b) What is his speed at the bottom of the swing if he pushes off with a speed of 5.00 m/s?
m/s

  • physics -

    (a) PE= mgh=mgL(1-cosα),
    KE= mv²/2.
    PE=KE
    mgL(1-cosα)= mv²/2,
    v=sqrt{2gL(1-cosα)}= ….
    (b) PE+KE1=KE
    mgL(1-cosα) + mv₀²/2= mv²/2,
    v = sqrt{2gL(1-cosα) + v₀²}= …

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