Post a New Question


posted by .

A spring gun (k = 27.1 N/m) is used to shoot a 51.1-g ball horizontally. Initially the spring is compressed by 16.5 cm. The ball loses contact with the spring and leaves the gun when the spring is still compressed by 11.5 cm. What is the speed of the ball when it hits the ground, 1.41 m below the spring g

  • physics -

    kx₁²/2 -kx₂²/2 = mv(x)²/2
    Find v²(x)
    Vertical motion:
    h=gt²/2 => t=sqrt(2h/g)
    v=sqrt{v²(x)+ v²(y)}

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question