Assume a perfectly elastic collision between a 916g bat and a 145g baseball. Initially, the ball was moving at 32 m/s toward the ball and afterward it's heading away at 40 m/s.

Find bat's speed before and after collision.

The change in momentum of the ball equals that of the bat.

Vbat1 - Vbat2 = (0.145/0.916)*(40 + 32)
= 11.40 m/s

The bat slows down after hitting the ball.

Now use conservation of energy to solve for the bat's initial velocity, Mbat1.

(1/2)Mbat*Vbat1^2 + (1/2)Mball*34^2
= (1/2)Mbat*(Vbat1-11.40)^2 + (1/2)
Mball*40^2

To find the bat's speed before and after the collision, we can use the law of conservation of momentum. According to this law, the total momentum before the collision is equal to the total momentum after the collision.

Momentum = mass × velocity

Initially, the baseball's momentum can be calculated as:
Initial momentum of baseball = mass of baseball × initial velocity of baseball
P1 = 145g × 32 m/s

Similarly, the bat's momentum can be calculated as:
Initial momentum of bat = mass of bat × initial velocity of bat
P2 = 916g × V

After the collision, the baseball's momentum can be calculated as:
Final momentum of baseball = mass of baseball × final velocity of baseball
P3 = 145g × (-40 m/s) (negative because it's moving in the opposite direction)

Similarly, the bat's momentum can be calculated as:
Final momentum of bat = mass of bat × final velocity of bat
P4 = 916g × V'

According to the law of conservation of momentum, the total momentum before the collision (P1 + P2) should be equal to the total momentum after the collision (P3 + P4).

P1 + P2 = P3 + P4

Let's substitute the values:

145g × 32 m/s + 916g × V = 145g × (-40 m/s) + 916g × V'

Now, let's convert the mass into kilograms:
145g = 0.145kg
916g = 0.916kg

Substituting the values:
0.145kg × 32 m/s + 0.916kg × V = 0.145kg × (-40 m/s) + 0.916kg × V'

Simplifying this equation, we get:
0.145 × 32 + 0.916 × V = 0.145 × (-40) + 0.916 × V'

Solve this equation to find the value of V, which represents the bat's speed before the collision. Once you have V, you can use it to find V', which represents the bat's speed after the collision.

Note: Make sure to convert the final velocities to positive values if they represent the direction opposite to the initial velocity.