How do I write ZnSo4(aq)+Na3Po4(aq)---> Zn3(Po4)2(s)+Na2S04(aq)as a net ionic equation balanced?
3Zn^2+(aq) + 2PO4^3-(aq) ==> Zn3(PO4)2(s)
To write the balanced net ionic equation for the given chemical equation, follow these steps:
Step 1: Write the complete molecular equation.
ZnSO4(aq) + Na3PO4(aq) → Zn3(PO4)2(s) + Na2SO4(aq)
Step 2: Write the ionic equation by breaking the soluble compounds into their respective ions.
Zn2+(aq) + SO4^2-(aq) + 3Na+(aq) + PO4^3-(aq) → Zn3(PO4)2(s) + 2Na+(aq) + SO4^2-(aq)
Step 3: Identify the spectator ions, which are the ions that remain unchanged throughout the reaction.
In this case, the spectator ions are SO4^2-(aq) and Na+(aq).
Step 4: Write the net ionic equation by removing the spectator ions from the ionic equation.
Zn2+(aq) + 3PO4^3-(aq) → Zn3(PO4)2(s)
Therefore, the balanced net ionic equation is:
Zn2+(aq) + 3PO4^3-(aq) → Zn3(PO4)2(s)
To write the net ionic equation for the given chemical reaction, you need to first write the balanced molecular equation and then identify the strong electrolytes that dissociate into ions in water. From there, you can eliminate the spectator ions and write the net ionic equation.
Let's start by writing the balanced molecular equation for the reaction:
ZnSO4(aq) + Na3PO4(aq) → Zn3(PO4)2(s) + Na2SO4(aq)
Now, let's break down the compounds into their respective ions based on solubility rules and strong electrolytes:
ZnSO4(aq) → Zn2+(aq) + SO4^2-(aq)
Na3PO4(aq) → 3Na+(aq) + PO4^3-(aq)
Zn3(PO4)2(s) (no dissociation since it's a solid)
Na2SO4(aq) → 2Na+(aq) + SO4^2-(aq)
Next, we need to determine the spectator ions, which are the ions that are present on both sides of the equation and do not participate in the reaction. In this case, the Na+ ions and the SO4^2- ions are the spectator ions. Therefore, we can remove them from the equation:
Zn2+(aq) + PO4^3-(aq) → Zn3(PO4)2(s)
Finally, we have the net ionic equation:
Zn2+(aq) + PO4^3-(aq) → Zn3(PO4)2(s)
Therefore, the balanced net ionic equation is Zn2+(aq) + PO4^3-(aq) → Zn3(PO4)2(s).