Aaron has 20 dimes and nickels which together total is 1.40 how many of each does he have
number of nickels --- x
number of dimes ----20-x
5x + 10(20-x) = 140
5x + 200 - 10x = 140
-5x = -60
x = 12
Aaron has 12 nickels and 8 dimes
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To solve this problem, we can set up a system of equations. Let's represent the number of dimes as 'd' and the number of nickels as 'n'.
We are given two pieces of information. First, we know that Aaron has a total of 20 dimes and nickels, so we can write the equation:
d + n = 20
Second, we know that the value of all the coins combined is $1.40. Since a dime is worth 10 cents and a nickel is worth 5 cents, we can write another equation to represent the value:
10d + 5n = 140 (in cents)
Now, we can solve this system of equations to find the values of 'd' and 'n'.
Let's start by solving the first equation for 'n', by subtracting 'd' from both sides:
n = 20 - d
Substituting this value of 'n' into the second equation, we can solve for 'd':
10d + 5(20 - d) = 140
10d + 100 - 5d = 140
5d = 40
d = 8
Now that we have the value of 'd', we can substitute it back into the first equation to find 'n':
8 + n = 20
n = 20 - 8
n = 12
Therefore, Aaron has 8 dimes and 12 nickels.