A 110 kg object moves in a horizontal straight line with an initial speed of 54 m/s. If it is stopped along that line with a deceleration of 1.90 m/s2 what magnitude of force is required?
To find the magnitude of force required to stop the object, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.
Given:
Mass of the object (m) = 110 kg
Deceleration (a) = 1.90 m/s²
To find the force (F), we need to find the acceleration first. Since the object is being decelerated, the acceleration will have a negative value.
Acceleration (a) = -1.90 m/s²
Now we can calculate the force:
F = m * a
F = 110 kg * (-1.90 m/s²)
F = -209 N
Therefore, the magnitude of force required to stop the object is 209 N.
To find the magnitude of force required to stop the object, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).
Given:
Mass (m) = 110 kg
Acceleration (a) = -1.90 m/s² (negative sign indicates deceleration)
Using the formula:
F = m * a
Substituting the given values:
F = 110 kg * -1.90 m/s²
Now, we can calculate the magnitude of force:
F = -209 N
Therefore, the magnitude of force required to stop the object is 209 Newtons, acting in the opposite direction of the motion.