What is the slope, m, of the line that contains the points (-12, 16), (-3, 4) and (6,-8)?
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Choose any 2 points, I would choose, for example (-3,4) and (6,-8).
Then use the slope formula:
m=(y2-y1)/(x2-x1)
so it would be:
m=(-8-4)/(6+3)= -4/3
The slope is -4/3
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I'm sure that's right
I think that you're right too. Thank so much for your help.
Yo are welcome
To find the slope of a line passing through two points (x1, y1) and (x2, y2), we can use the formula:
m = (y2 - y1) / (x2 - x1)
Let's calculate the slope using the given points (-12, 16), (-3, 4):
m1 = (4 - 16) / (-3 - (-12))
= (4 - 16) / (-3 + 12)
= (-12) / 9
= -4/3
Now let's calculate the slope using the points (-3, 4), (6, -8):
m2 = (-8 - 4) / (6 - (-3))
= (-8 - 4) / (6 + 3)
= (-12) / 9
= -4/3
Since the slope is the same for both pairs of points, we can conclude that the line passing through the points (-12, 16), (-3, 4), and (6, -8) has a slope of -4/3.