Find the following values for each function
a. f(0)
b. f(-1)
c. f(-x)
d. f(x+1)
f(x)=2x^2+3x-4
I you plug in the value for each x, I just want to check my answers. Thanks.
To find the values for each function, we need to plug in the given values of x into the function expression f(x) = 2x^2 + 3x - 4 and evaluate it.
a. f(0):
To find f(0), we substitute 0 in place of x in the function:
f(0) = 2(0)^2 + 3(0) - 4
= 0 + 0 - 4
= -4
b. f(-1):
To find f(-1), we substitute -1 in place of x in the function:
f(-1) = 2(-1)^2 + 3(-1) - 4
= 2(1) - 3 - 4
= 2 - 3 - 4
= -5
c. f(-x):
To find f(-x), we substitute -x in place of x in the function:
f(-x) = 2(-x)^2 + 3(-x) - 4
= 2x^2 - 3x - 4
d. f(x + 1):
To find f(x + 1), we substitute (x + 1) in place of x in the function:
f(x + 1) = 2(x + 1)^2 + 3(x + 1) - 4
= 2(x^2 + 2x + 1) + 3(x + 1) - 4
= 2x^2 + 4x + 2 + 3x + 3 - 4
= 2x^2 + 7x + 1
Therefore, the values for each function are:
a. f(0) = -4
b. f(-1) = -5
c. f(-x) = 2x^2 - 3x - 4
d. f(x + 1) = 2x^2 + 7x + 1