College Physics

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Okay so the acceleration g on this planet X is 15 m/s^2

I have solved for all answers but this one.

How long would it take the object to reach a height of 14.1 ? For an object thrown upward there are two times it would be at any hieght. Give the going up answer, a comma, and give the going down answer.


How do we go about this?

  • College Physics -

    Assuming that accelerations is constant,
    Given: a=15 ms^-2, s=14.1 m

    Applying kinematics equation,
    v^2 = u^2 + 2as

    Find for u since v is 0,
    u= sqrt(2 x -15 x -14.1)
    = 20.78

    Solve for t,
    s= ut + 0.5at^2
    14.1= 20.78t + 0.5(15)t^2
    //Solve quadratic eqn for t
    t= 0.564(Ans), -3.33(not possible)

  • College Physics -

    Solving for t,
    14.1=20.78t-.5(15)t^2
    subtract using a -15m/s^2 (downward acceleration due to gravity)

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