A car accelerates uniformly in a straight line from rest at the rate of 3.2 m/s2.
What is the speed of the car after it has traveled 58 m?
Answer in units of m/s
How long does it take the car to travel 58 m? Answer in units of s
To find the speed of the car after it has traveled 58 m, we can use the equation of motion:
v^2 = u^2 + 2aS
Where:
v = final velocity (speed)
u = initial velocity (initial speed)
a = acceleration
S = distance
Given:
u = 0 (the car starts from rest)
a = 3.2 m/s^2
S = 58 m
Using the equation, we can calculate the final velocity:
v^2 = 0^2 + 2 * 3.2 * 58
v^2 = 0 + 371.2
v^2 = 371.2
v = √371.2
v ≈ 19.26 m/s
So, the speed of the car after it has traveled 58 m is approximately 19.26 m/s.
Next, to find the time it takes for the car to travel 58 m, we can use another equation of motion:
v = u + at
Rearranging the equation, we have:
t = (v - u) / a
Using the given values, we can find the time:
t = (19.26 - 0) / 3.2
t ≈ 6.02 s
Therefore, it takes approximately 6.02 seconds for the car to travel 58 m.